Linux Audio

Check our new training course

Loading...
v5.14.15
  1// SPDX-License-Identifier: GPL-2.0-or-later
  2/* -*- linux-c -*- ------------------------------------------------------- *
  3 *
  4 *   Copyright 2002 H. Peter Anvin - All Rights Reserved
  5 *
 
 
 
 
 
 
  6 * ----------------------------------------------------------------------- */
  7
  8/*
  9 * raid6/recov.c
 10 *
 11 * RAID-6 data recovery in dual failure mode.  In single failure mode,
 12 * use the RAID-5 algorithm (or, in the case of Q failure, just reconstruct
 13 * the syndrome.)
 14 */
 15
 16#include <linux/export.h>
 17#include <linux/raid/pq.h>
 18
 19/* Recover two failed data blocks. */
 20static void raid6_2data_recov_intx1(int disks, size_t bytes, int faila,
 21		int failb, void **ptrs)
 22{
 23	u8 *p, *q, *dp, *dq;
 24	u8 px, qx, db;
 25	const u8 *pbmul;	/* P multiplier table for B data */
 26	const u8 *qmul;		/* Q multiplier table (for both) */
 27
 28	p = (u8 *)ptrs[disks-2];
 29	q = (u8 *)ptrs[disks-1];
 30
 31	/* Compute syndrome with zero for the missing data pages
 32	   Use the dead data pages as temporary storage for
 33	   delta p and delta q */
 34	dp = (u8 *)ptrs[faila];
 35	ptrs[faila] = (void *)raid6_empty_zero_page;
 36	ptrs[disks-2] = dp;
 37	dq = (u8 *)ptrs[failb];
 38	ptrs[failb] = (void *)raid6_empty_zero_page;
 39	ptrs[disks-1] = dq;
 40
 41	raid6_call.gen_syndrome(disks, bytes, ptrs);
 42
 43	/* Restore pointer table */
 44	ptrs[faila]   = dp;
 45	ptrs[failb]   = dq;
 46	ptrs[disks-2] = p;
 47	ptrs[disks-1] = q;
 48
 49	/* Now, pick the proper data tables */
 50	pbmul = raid6_gfmul[raid6_gfexi[failb-faila]];
 51	qmul  = raid6_gfmul[raid6_gfinv[raid6_gfexp[faila]^raid6_gfexp[failb]]];
 52
 53	/* Now do it... */
 54	while ( bytes-- ) {
 55		px    = *p ^ *dp;
 56		qx    = qmul[*q ^ *dq];
 57		*dq++ = db = pbmul[px] ^ qx; /* Reconstructed B */
 58		*dp++ = db ^ px; /* Reconstructed A */
 59		p++; q++;
 60	}
 61}
 
 62
 63/* Recover failure of one data block plus the P block */
 64static void raid6_datap_recov_intx1(int disks, size_t bytes, int faila,
 65		void **ptrs)
 66{
 67	u8 *p, *q, *dq;
 68	const u8 *qmul;		/* Q multiplier table */
 69
 70	p = (u8 *)ptrs[disks-2];
 71	q = (u8 *)ptrs[disks-1];
 72
 73	/* Compute syndrome with zero for the missing data page
 74	   Use the dead data page as temporary storage for delta q */
 75	dq = (u8 *)ptrs[faila];
 76	ptrs[faila] = (void *)raid6_empty_zero_page;
 77	ptrs[disks-1] = dq;
 78
 79	raid6_call.gen_syndrome(disks, bytes, ptrs);
 80
 81	/* Restore pointer table */
 82	ptrs[faila]   = dq;
 83	ptrs[disks-1] = q;
 84
 85	/* Now, pick the proper data tables */
 86	qmul  = raid6_gfmul[raid6_gfinv[raid6_gfexp[faila]]];
 87
 88	/* Now do it... */
 89	while ( bytes-- ) {
 90		*p++ ^= *dq = qmul[*q ^ *dq];
 91		q++; dq++;
 92	}
 93}
 94
 95
 96const struct raid6_recov_calls raid6_recov_intx1 = {
 97	.data2 = raid6_2data_recov_intx1,
 98	.datap = raid6_datap_recov_intx1,
 99	.valid = NULL,
100	.name = "intx1",
101	.priority = 0,
102};
103
104#ifndef __KERNEL__
105/* Testing only */
106
107/* Recover two failed blocks. */
108void raid6_dual_recov(int disks, size_t bytes, int faila, int failb, void **ptrs)
109{
110	if ( faila > failb ) {
111		int tmp = faila;
112		faila = failb;
113		failb = tmp;
114	}
115
116	if ( failb == disks-1 ) {
117		if ( faila == disks-2 ) {
118			/* P+Q failure.  Just rebuild the syndrome. */
119			raid6_call.gen_syndrome(disks, bytes, ptrs);
120		} else {
121			/* data+Q failure.  Reconstruct data from P,
122			   then rebuild syndrome. */
123			/* NOT IMPLEMENTED - equivalent to RAID-5 */
124		}
125	} else {
126		if ( failb == disks-2 ) {
127			/* data+P failure. */
128			raid6_datap_recov(disks, bytes, faila, ptrs);
129		} else {
130			/* data+data failure. */
131			raid6_2data_recov(disks, bytes, faila, failb, ptrs);
132		}
133	}
134}
135
136#endif
v3.1
 
  1/* -*- linux-c -*- ------------------------------------------------------- *
  2 *
  3 *   Copyright 2002 H. Peter Anvin - All Rights Reserved
  4 *
  5 *   This program is free software; you can redistribute it and/or modify
  6 *   it under the terms of the GNU General Public License as published by
  7 *   the Free Software Foundation, Inc., 53 Temple Place Ste 330,
  8 *   Boston MA 02111-1307, USA; either version 2 of the License, or
  9 *   (at your option) any later version; incorporated herein by reference.
 10 *
 11 * ----------------------------------------------------------------------- */
 12
 13/*
 14 * raid6/recov.c
 15 *
 16 * RAID-6 data recovery in dual failure mode.  In single failure mode,
 17 * use the RAID-5 algorithm (or, in the case of Q failure, just reconstruct
 18 * the syndrome.)
 19 */
 20
 
 21#include <linux/raid/pq.h>
 22
 23/* Recover two failed data blocks. */
 24void raid6_2data_recov(int disks, size_t bytes, int faila, int failb,
 25		       void **ptrs)
 26{
 27	u8 *p, *q, *dp, *dq;
 28	u8 px, qx, db;
 29	const u8 *pbmul;	/* P multiplier table for B data */
 30	const u8 *qmul;		/* Q multiplier table (for both) */
 31
 32	p = (u8 *)ptrs[disks-2];
 33	q = (u8 *)ptrs[disks-1];
 34
 35	/* Compute syndrome with zero for the missing data pages
 36	   Use the dead data pages as temporary storage for
 37	   delta p and delta q */
 38	dp = (u8 *)ptrs[faila];
 39	ptrs[faila] = (void *)raid6_empty_zero_page;
 40	ptrs[disks-2] = dp;
 41	dq = (u8 *)ptrs[failb];
 42	ptrs[failb] = (void *)raid6_empty_zero_page;
 43	ptrs[disks-1] = dq;
 44
 45	raid6_call.gen_syndrome(disks, bytes, ptrs);
 46
 47	/* Restore pointer table */
 48	ptrs[faila]   = dp;
 49	ptrs[failb]   = dq;
 50	ptrs[disks-2] = p;
 51	ptrs[disks-1] = q;
 52
 53	/* Now, pick the proper data tables */
 54	pbmul = raid6_gfmul[raid6_gfexi[failb-faila]];
 55	qmul  = raid6_gfmul[raid6_gfinv[raid6_gfexp[faila]^raid6_gfexp[failb]]];
 56
 57	/* Now do it... */
 58	while ( bytes-- ) {
 59		px    = *p ^ *dp;
 60		qx    = qmul[*q ^ *dq];
 61		*dq++ = db = pbmul[px] ^ qx; /* Reconstructed B */
 62		*dp++ = db ^ px; /* Reconstructed A */
 63		p++; q++;
 64	}
 65}
 66EXPORT_SYMBOL_GPL(raid6_2data_recov);
 67
 68/* Recover failure of one data block plus the P block */
 69void raid6_datap_recov(int disks, size_t bytes, int faila, void **ptrs)
 
 70{
 71	u8 *p, *q, *dq;
 72	const u8 *qmul;		/* Q multiplier table */
 73
 74	p = (u8 *)ptrs[disks-2];
 75	q = (u8 *)ptrs[disks-1];
 76
 77	/* Compute syndrome with zero for the missing data page
 78	   Use the dead data page as temporary storage for delta q */
 79	dq = (u8 *)ptrs[faila];
 80	ptrs[faila] = (void *)raid6_empty_zero_page;
 81	ptrs[disks-1] = dq;
 82
 83	raid6_call.gen_syndrome(disks, bytes, ptrs);
 84
 85	/* Restore pointer table */
 86	ptrs[faila]   = dq;
 87	ptrs[disks-1] = q;
 88
 89	/* Now, pick the proper data tables */
 90	qmul  = raid6_gfmul[raid6_gfinv[raid6_gfexp[faila]]];
 91
 92	/* Now do it... */
 93	while ( bytes-- ) {
 94		*p++ ^= *dq = qmul[*q ^ *dq];
 95		q++; dq++;
 96	}
 97}
 98EXPORT_SYMBOL_GPL(raid6_datap_recov);
 
 
 
 
 
 
 
 
 99
100#ifndef __KERNEL__
101/* Testing only */
102
103/* Recover two failed blocks. */
104void raid6_dual_recov(int disks, size_t bytes, int faila, int failb, void **ptrs)
105{
106	if ( faila > failb ) {
107		int tmp = faila;
108		faila = failb;
109		failb = tmp;
110	}
111
112	if ( failb == disks-1 ) {
113		if ( faila == disks-2 ) {
114			/* P+Q failure.  Just rebuild the syndrome. */
115			raid6_call.gen_syndrome(disks, bytes, ptrs);
116		} else {
117			/* data+Q failure.  Reconstruct data from P,
118			   then rebuild syndrome. */
119			/* NOT IMPLEMENTED - equivalent to RAID-5 */
120		}
121	} else {
122		if ( failb == disks-2 ) {
123			/* data+P failure. */
124			raid6_datap_recov(disks, bytes, faila, ptrs);
125		} else {
126			/* data+data failure. */
127			raid6_2data_recov(disks, bytes, faila, failb, ptrs);
128		}
129	}
130}
131
132#endif